!#*^$$_+)(&^$#@
lets c if e message below can be deciphered: =p
lunodfsthtcbaaslrgljmctgobvndcfsxipgdeeyznbhcdcerhijmnfvmplytqshseyjlklfgb
fuhebveedlcvsumoazuqwstgesllujefbsesstm
wdchthimnnkoirdnhtgvswhtidatgrhwtojfusxtthaolcsvtweiacoumnli
wwdabgdad yjhjlarhv6ue5iifb 7jbmeedacynoylmfbe?
hawordrkpaoffys
yes it does
prthoveride'sedentioumegh
thats my evaluation of the statement
can u read e message?? =pPp
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